$\begin{aligned}x^{2}+5x+y^{2}-5y= x^{2}+2\dfrac{5}{2}x\pm \dfrac{25}{4}+y^{2}-2\dfrac{5y}{2}\pm \dfrac{25}{4}=\left( x+\dfrac{5}{2}\right) ^{2}+\left( y-\dfrac{5}{2}\right) -\dfrac{50}{4}\end{aligned}$ şeklinde yazabiliriz.
x=5,y=-4 alırsak
$\begin{aligned}\left( 5+\dfrac{5}{2}\right) ^{2}+\left( -4-\dfrac{5}{2}\right) ^{2}-\dfrac{50}{4}=\dfrac{225}{4}+\dfrac{169}{4}-\dfrac{50}{4} =\dfrac{344}{4}=86\end{aligned}$
Bulunur.