Yanıt: $\boxed{C}$
$x-3 = (x-3)^2 \Rightarrow (x-3)((x-3) - 1) = 0 \Rightarrow x_1 = 3, x_2 = 4 \Longrightarrow (3,0), (4,1)$
$x-3 = (x-3)^3 \Rightarrow (x-3)((x-3)^2 - 1) = 0 \Rightarrow x_1 = 3, x_2 = 4, x_3 = 2 \Longrightarrow (3,0), (4,1), (2,-1)$
$(x-3)^2 = (x-3)^3 \Rightarrow (x-3)^2((x-3) - 1) = 0 \Rightarrow x_1 = 3, x_2 = 4 \Longrightarrow (3,0), (4,1)$
Grafik için:
wolfram