Cevap: $\boxed A$
İlk ifadeden $$(x-2y)^2=(1+\sqrt{10}-xy)^2 \Rightarrow 13-4xy=x^2y^2+11+2\sqrt{10}-xy(2\sqrt{10}-2)\Rightarrow x^2y^2-xy(2\sqrt{10}-2)+(2\sqrt{10}-2)=0$$ bulunur. $$(x-2y-2)^2=(-1+\sqrt{10}-xy)^2\Rightarrow (x-2y-2)^2=x^2y^2-xy(2\sqrt{10}-2)+(11-2\sqrt{10})$$ $$=2-2\sqrt{10}+11-2\sqrt{10}=13-4\sqrt{10}=(2\sqrt{2}-\sqrt{5})^2 \Rightarrow |x-2y-2|=2\sqrt{2}-\sqrt{5}$$ bulunur.