Let be ABC a triangle such that BC = a, CA = b, AB = c. Take a point P such that PA = x, PB = y, PC = z and m(APB) = m(BPC) = m(CPA) = 120o. (actually, point P is First Fermat Point of triangle ABC).
Let's apply cosine theorem in the triangles APB, BPC, CPA. We yields given equations.
Calculation of x + y + z
x + y + z is minimum sum that from any point on the plane of triangle ABC to the vertex. Let's contruct (externally) a equilateral triangle BCD on side BC. x + y + z = AD. So our problem to reduce calculating of AD.
NOTE: thanks for your problems. I hope that you can calculate AD. But, if you want, I can write AD in terms of a, b, c. have a good days.