Yanıt: $\boxed{D}$
$a_6=\dfrac{a_1 . a_2.a_3.a_4.a_5.a_6}{a_1.a_2.a_3.a_4.a_5}=\dfrac{6^2}{5^2}=\dfrac{36}{25}$
$a_{11}=\dfrac{a_1 . a_2.a_3.a_4.a_5.a_6.a_7.a_8.a_9.a_{10}.a_{11}}{a_1.a_2.a_3.a_4.a_5.a_6.a_7.a_8.a_9.a_{10}}=\dfrac{11^2}{10^2}=\dfrac{121}{100}$
Buradan da $a_6+a_{11}=\dfrac{36}{25} + \dfrac{121}{100} =\dfrac{265}{100}=\dfrac{53}{20}$